If you look at the pedigree page of an animal you’ll see a tab with statistics. These are genetic statistics like the genetic code, the COI, AVK, ECG and PC. If you’re unknown with these term, it might be hard to figure out what it means exactly.

Genetic code

The genetic code is a series of color mutations translated into simple codes that all aligned, describe the color of the animal and which genes it carries with it. With the genetic code and the gencalc, you can calculate pairing and figure out which colors will pop up in a planned litter. Ofcourse we can do that for you if it’s just a bit above your head! But for those who are well known in genetic calculations, it might give some extra insight on your breeding herd.


COI is the abbrevation for “inbreeding coefficient”. We speak of inbreeding when two animals have similar animals within their background. Inbreeding also is explained in coefficiencies to tell how much two animals look alike genetically. When two parents have young, they both give 50% of their genes to their young. Therefore a young is always 50% related to their mother and 50% to their father. Depending on how many similar parents they have and how far apart those parents are, the COI is calculated. But when an inbred hedgehog is mated to an unrelated hedgehog, the COI will display 0%. That’s where the AVK comes in.


The abbrevation of AVK is German and stands for “AhnenVerlust-Koeffizient” which translates to ancestor loss coefficient. This coefficient check how many double animals there are in a pedigree up to 10 generations. If all ancestors are unique within the pedigree the AVK is 100%, but if there has been some linebreeding, the value will be lower.
For example: If all 10 generations are complete, there are 2048 animals within the pedigree. If all of these ancestors are unique, the AVK value is 100%. But, if six ancestors are similar, you’ll have 2048-6=2042 unique ancestors left. Than you can calculate the avk by taking the amount of unique ancestors (2042) and devide it by the amount of unique animals should be in the pedigree (2048) and then multiply by 100. That makes up for the calculation 2042/2048×100= 99,70% AVK.
So with COI and AVK combined, you’ll have a pretty good idea on how much inbreeding or linebreeding has been conducted within an animal. The COI might disappear on an animal as soon as it’s mated to an unrelated partner, but the AVK will still show the previous inbreeding.


ECG is the abbrevation of “Equivalent Complete Generations” which as it sounds like, calculates how many generations are known. This adds to the COI and AVK, because a COI might be 0% and the AVK might be 100%, but if there are no or hardly any known previous generations, these statistics are meaningless. The ECG gives every known ancestor a certain point score and adds them up to each other. The ECG is calculated with these points:

The program adds up every ancestor. For example: If you know both parents of an animal but haven’t got any further information than the ECG is 0,5+0,5=1. If the grandparents are also know the ECG is (0,5×2)+(0,25×4)=2. But if you only have both parents and the grandparents on mothers side, the ECG will be (0,5×2)+(0,25×2)=1,5. Conclusion: the higher the score, the more chance the COI is a good reflection of reality.


PC stands for “Pedigree Completeness” and is used in almost the same way as ECG, but instead this equivalent only counts the amount of complete generations. So for example if you have an animal of which the parents are known, but you only have information on both parents on mothers side, the ECG will be 1,5. The PC looks only at the complete generations and will be 1. If the ECG is 2,5 though, it’s not always the case that the PC will also be 2!
For example: You have an animal that has both parents known, but only the mother has further information. On her side, you have one parent, two grandparents, four great grandparents and eight great grandparents. The ECG will give a score of 2,5, but there is only one complete generation within the pedigree, so the PC will be 1.

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